Question

Tìm x:

a) \(\dfrac{1}{2}+\dfrac{2}{3}x=\dfrac{1}{4}\)

b) \(2\dfrac{2}{3}:x=1\dfrac{7}{9}:0,02\)

c) \(x^x-x+1=1\)

d) \(5-\left|3x-1\right|=3\)

Answer 1

a) \(\dfrac{1}{2}+\dfrac{2}{3}x=\dfrac{1}{4}\\ \Rightarrow\dfrac{2}{3}x=-\dfrac{1}{4}\\ \Rightarrow x=-\dfrac{3}{8}\)

b) \(2\dfrac{2}{3}:x=1\dfrac{7}{9}:0,02\\ \Rightarrow2\dfrac{2}{3}:x=\dfrac{800}{9}\\ \Rightarrow x=\dfrac{3}{100}\)

c) \(x^x-x+1=1\\ \Rightarrow x^x-x=0\\ \Rightarrow x^x=x\\ \Rightarrow x=1\)

d) \(5-\left|3x-1\right|=3\\ \Rightarrow\left|3x-1\right|=2\\ \Rightarrow\left[{}\begin{matrix}3x-1=-2\\3x-1=2\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=-\dfrac{1}{3}\\x=1\end{matrix}\right.\)

Answer 2

a, x=-3/8

b,x=3/100

c,x=0

d,x=-1/3 hoặc x=1