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Bài 2:Tìm x
a) |x-2|-\(\dfrac{3}{5}\)=\(\dfrac{1}{2}\)
b) (x-\(\dfrac{7}{3}\)):\(\dfrac{-1}{3}\)=0,4
c) |x-3|=5
d) (2x+3)\(^2\)=25
e) \(\dfrac{3}{4}\)+\(\dfrac{1}{4}\): x=\(\dfrac{2}{5}\)
f) (x-\(\dfrac{1}{2}\))\(^3\)=\(\dfrac{1}{27}\)
Làm nhanh giúp mik vs ạ(đang rất cần, cảm ơn nhiều ạaa!!!!!)
Tìm x,y biết:
1) 3^X-1 = 1/243
2) 81^-2X x 27^X=9^5
3) ( x-y+3)^2 + (y-1)^2=0
Tìm x:
h) (1-2)2 - 1/2=0
k) ( x+1)3 + 27 =0
m) ( 3x+1/2)3+1/27=0
l) x3 - x= 0
n) x2 + 1/2x=0
Tim xthuoc Z biet:
1,|2x-5|-|2x+9|=0
2,|x+1|-|x+2|-|3-x|=7
3,|2x+3|+|3x+2|-|4-x|=10
1)tim x bit a)(1/2-1/3).6^x+6^x+2=6^15+6^18
b)3^x+3^x+2=2430
c)(2x-15)^5=(2x-15)^3
2) so saanh
a)2^11 va 5^35
b)2^31 va 3^21
c)2^15 va 27^5.49^8 d)21^15 va 27^5.49^8
Tìm x
(x -1)3=27
x2+x=0
(2x+1)2=25
(2x-3)2=36
(x-1)x+2=(x-1)x+4
(2x-1)3=-8
Tim x, biet;
a/ (x-1)^2=0
b/ (x-2)^2-1=0
c/ (2x-1)^3=-8
d/ (x+2)^2+1=0
bai 1: Tim x
a) (x-1)^3 =27
b ( 2x +1)^2=25
c) (x-1)^x+2=(x-1)x+4
d) ( 2x-1)^3 =-8
e) 2^2x-2x=96
GIUP MK VOI NHA MK DANG CAN GAP LAM
