a. \(\left(27-x\right)\cdot2018=0\)
\(\left(27-x\right)=0\text{ : }2018\)
\(\left(27-x\right)=0\)
\(x=0+27\)
\(x=27\)
b. \(27\cdot x+23\cdot x=100\)
\(\left(27+23\right)\cdot x=100\)
\(50\cdot x=100\)
\(x=100\text{ : }50\)
\(x=2\)
a, (27-x).2018=0
27-x=0:2018
27-x=0
x=27-0
x=27
b,27.x+23.x=100
x.(27+23)=100
x.50=100
x=100:50
x=2
tk mk nha
a. ( 27-x ) . 2018 = 0
27-x = 0 : 2018
27-x = 0
x = 27-0
x = 27
Vậy x = 27.
b. 27. x + 23 . x = 100
( 27 + 23 ) . x = 100
50 . x = 100
x = 100 : 50
x = 2
Vậy x = 2
B=27.x+23.x=100
( 27+23).x=100
100.x=100
X=100:100
X=1
A=(27.x).2018=0
(27-x). =0.2018.
(27-x). =0
X= 0+27
X=27
a) \(\left(27-x\right).2018=0\)
\(\Rightarrow27-x=0:2018\)
\(\Rightarrow27-x=0\)
\(\Rightarrow x=27-0\)
\(\Rightarrow x=27\)
Vậy x = 27
b) \(27.x+23.x=100\)
\(\Rightarrow\left(27+23\right).x=100\)
\(\Rightarrow50.x=100\)
\(\Rightarrow x=100:50\)
\(\Rightarrow x=2\)
Vậy x = 2
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