Question

Tìm X

a) 136 – X = 400:8+7

b) x+x+x+15=21

c) 35+X+27=80

Answer 1

a)136-x=400/8+7

136-x=50+7

136-x=57

x=136-57

x=79

b)x+x+x+15=21

3x=21-15

3x=6

x=6/3

x=2

c)35+x+27=80

62+x=80

x=80-62

x=18

Answer 2

a)136-x=400:8+7

136-x=57

x=136-57

x=79

b)x+x+x+15=21

x*3+15=21

x*3=21-15

x=6:3

x=2

c)35+x+27=80

35+x=80-27

x=53-35

x=18

Answer 3

a/136 - x = 400 : 8 + 7

136 - x    = 57

x            = 136 - 57

x            = 79

b/ x + x + x + 15 =21

x +x +x              = 21 - 15 

x +x +x              = 6

x                       = 6 : 3

x                       = 2

c/ 35 +x + 27 = 80

35 + 27 +x     = 80

62 + x           = 80

x                   = 80-62

x                   =  18

Answer 4

a) 136 – X = 400:8+7

136-X=57

=>x=79

b) x+x+x+15=21

=>3x+15=21

=>3x=6

=>x=2

c) 35+X+27=80

=>x+(35+27)=80

=>x+62=80

=>x=18

Answer 5

a)136 – X = 400 : 8 + 7

   136 – X =    50 + 7

   136 – X =       57

         X      =   136 – 57

         X      =       79

b) x + x + x + 15 = 21

         x X 3           = 21 – 15

         x X 3           =     6

            x              =   6 : 3

            x              =      2

c) 35 + x + 27 = 80

 ( 35 + 27 ) + x= 80

62                     + x= 80

             x        = 80 – 62

             x        = 18