9x-1 = 9
9x-1 = 91
suy ra x-1=1
x=1+1
x=2
ta có 9^x-1=9
Suy ra 9^x-1=9^1
Suy ra x-1=1
Suy ra x=1+1
Suy ra x=2
Vậy x=2
ta có:9^x-1=9
hay 9^x-1=9^1
=>x-1=1
=>x=1+1=2
Vậy x=2
\(9^{x-1}=9\)
\(\Rightarrow9^{x-1}=9^1\)
\(\Rightarrow x-1=1\)
\(\Rightarrow x=1+1\)
\(\Rightarrow x=2\)
Vậy \(x=2\)
\(9^{x-1}=9\)
\(9^{x-1}=9^1\)
\(\Rightarrow x-1=1\)
\(\Rightarrow x=2\)
vậy \(x=2\)
9x-1=9
9x-1=91
x-1=1
x=1+1
x=2
Vây x =2
\(9^{x-1}=9\)
\(9^{x-1}=9^1\)
\(\Rightarrow\)\(x-1=1\)
\(x=1+1=2\)
Vậy x = 2