\(8^x.16^{-2x}=4^5\)
\(\Leftrightarrow8^x.8^{-2x}.2^{-2x}=4^5\)
\(\Leftrightarrow8^{x+\left(-2x\right)}.2^{-2x}=\left(2^2\right)^5\)
\(\Leftrightarrow8^{-x}=2^{10}:2^{-2x}\)
\(\Leftrightarrow8^{-x}=2^{10-\left(-2x\right)}=2^{10+2x}\)
\(\Leftrightarrow\left(2^3\right)^{-x}=2^{10+2x}\)
\(\Leftrightarrow2^{-3x}=2^{10+2x}\)
\(\Leftrightarrow-3x=10+2x\)
\(\Leftrightarrow5x=-10\)
\(\Leftrightarrow x=-2\)
Vậy : \(x=-2\)
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