Question

tìm x:
\(4\left(x-3\right)^2-\left(2x-1\right)\left(2x+1\right)=10\)

Answer 1

\(4(x-3)^2-(2x-1)(2x+1)=10\\\Rightarrow4(x^2-6x+9)-(4x^2-1)=10\\\Rightarrow4x^2-24x+36-4x^2+1=10\\\Rightarrow-24x+37=10\\\Rightarrow-24x=-27\\\Rightarrow x=\dfrac98\)