\(\dfrac{1313}{2828}+x=\dfrac{2323}{4646}\\ \dfrac{13}{28}+x=\dfrac{1}{2}\\ x=\dfrac{1}{2}-\dfrac{13}{28}\\ x=\dfrac{14}{28}-\dfrac{13}{28}\\ x=\dfrac{1}{28}\)
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1313/2828 + x = 2323/4646
13/28 + x = 23/46
1/2 + x = 1/2
x = 1/2 - 1/2
x = 0
Vậy x = 0
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