Question

tìm x

12-(3-x)=3x+1

/x-5/+/x^2-25/=0

Answer 1

12-(3-x)=3x+1

12-3+x=3x+1

9+x=3x+1

8=2x

x=4

b, vì /x-5/\(\ge\)0

       /x²-25/\(\ge\)  0

nến \(\hept{\begin{cases}x-5=0\\x^2-25=0\end{cases}}\)

\(\Rightarrow\)x=5

Answer 2

\(12-\left(3-x\right)=3x+\)\(1\)

\(12-3+x=3x+1\)

\(12-3-1=3x-x\)

\(8=2x\)

\(x=4\)