Question

tìm  X

1/17 + 1/2 = 3x - 3/2

Answer 1

\(\frac{1}{17}+\frac{1}{2}=3x-\frac{3}{2}\)

\(\frac{2}{34}+\frac{17}{34}=3x-\frac{3}{2}\)

\(\frac{19}{34}=3x-\frac{3}{2}\)

\(3x=\frac{19}{34}+\frac{3}{2}=\frac{19}{34}+\frac{51}{34}\)

\(3x=\frac{70}{34}\)

\(\Rightarrow x=\frac{70}{34}\div3=\frac{70}{34\cdot3}=\frac{35}{51}\)

\(\Rightarrow x=-\frac{16}{17}\div3=-\frac{16}{51}\)

Answer 2

\(\frac{1}{17}+\frac{1}{2}=3x-\frac{3}{2}\)

\(\frac{19}{34}=3x-\frac{3}{2}\)

\(\frac{35}{17}=3x\)

\(\frac{35}{17}\div3=x\)

\(\frac{35}{51}=x\)

Vậy ...

Answer 3

1/17 + 1/2 = 3x - 3/2

19/34        = 3x - 3/2

3x - 3/2     = 19/34

3x            = 19/34 + 3/2

3x            = 34/17 

  x            = 34/17 : 3

  x            = 2/3

Answer 4

1/7+1/2=3x-3/2

1/7+1/2+3/2=3x

9/14+3/2=3x

15/7=3x

15/7 : 3=x

5/7=x

Answer 5

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