Question

Tìm x:

1) \(\text{(x−1):0,16=−9:(1−x)}\)

2) \(\left(\left|x\right|-\dfrac{3}{2}\right)\left(2x^2-10\right)=0\)

3)\(8\sqrt{x}=x^2\left(x\ge0\right)\)

 

Answer 1

Mn ơi giúp mk với , cảm ơn nhiều !!

Answer 2

1) (x−1):0,16=−9:(1−x)

\(\Rightarrow\)(x-1):0,16= 9:(-1):(x-1)

\(\Rightarrow\)(x-1):0,16=9:(x-1)

\(\Rightarrow\)(x-1).(x-1)= 9. 0,16

\(\Rightarrow\)(x-1)\(^2\)= 1,44=1,2\(^2\)=(-1,2)\(^2\)

\(\Rightarrow\)x-1=1,2\(\Rightarrow\)x=2,2

hoặc x-1= -1,2\(\Rightarrow\)x= -0,2

Vậy x =2,2 ; x=0,2

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