Question

Tìm x, y biết:

\(\frac{x}{13}\)= \(\frac{-15}{39}\)= \(\frac{20}{3y}\)

GIÚP MÌNH VỚI MÌNH CẦN GẤP

Answer 1

\(\frac{x}{13}=\frac{-15}{39}=\frac{20}{3y}\)

\(\Leftrightarrow\orbr{\begin{cases}\frac{x}{13}=\frac{-15}{39}\\\frac{20}{3y}=\frac{-15}{39}\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=\left(-\frac{15}{39}\right)\cdot13\\-45y=780\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=-5\\y=\frac{780}{-45}=-\frac{52}{3}\end{cases}}\)

Vậy x = -5 và y = \(\frac{-52}{3}\)

Answer 2

\(\frac{\times}{13}=\frac{-15}{39};\frac{-15}{39}=\frac{20}{3y}\)

\(\Rightarrow\frac{3\times}{39}=\frac{-15}{39};\frac{-60}{156}=\frac{-60}{-9y}\)

\(\Rightarrow3\times=-15;-9y=156\)

\(\Rightarrow\times=-5;y=\frac{-52}{3}\)