Question

Tìm x , y biết 

( x- 3,5 )^{2 +} ( y - \(\frac{1}{10}\))⁴ < hoặc = 0

Answer 1

Ta có : \(\hept{\begin{cases}\left(x-3,5\right)^2\ge0;\forall x\\\left(y-\frac{1}{10}\right)^4\ge0;\forall y\end{cases}\Rightarrow}\left(x-3,5\right)^2+\left(y-\frac{1}{10}\right)^4\ge0;\forall x,y\)

Mà \(\left(x-3,5\right)^2+\left(y-\frac{1}{10}\right)^4\le0\)( theo đề bài )

\(\Rightarrow\left(x-3,5\right)^2+\left(y-\frac{1}{10}\right)^4=0\)

\(\Leftrightarrow\hept{\begin{cases}\left(x-3,5\right)^2=0\\\left(y-\frac{1}{10}\right)^4=0\end{cases}}\)

\(\Leftrightarrow\hept{\begin{cases}x=3,5\\y=\frac{1}{10}\end{cases}}\)

Vậy \(\hept{\begin{cases}x=3,5\\y=\frac{1}{10}\end{cases}}\)