\(x^2=\frac{5}{7}.x\)
Chia mỗi vế cho x ta được
\(x^2:x=\frac{5}{7}.x:x\)
\(x=\frac{5}{7}\)
\(x^2=\frac{5}{7}x\frac{5}{7}=>x=\frac{5}{7}\)
Tìm x biết \(\frac{x+4}{5}+\frac{x+2}{7}=\frac{x+5}{4}+\frac{x+7}{2}\)
Tìm x, biết:
a) \(\frac{x+5}{5}+\frac{x+5}{7}+\frac{x+5}{9}=\frac{x+5}{11}+\frac{x+5}{13}\)
b)\(\frac{x+2}{100}+\frac{x+3}{99}+\frac{x+4}{98}=\frac{x+5}{97}+\frac{x+6}{96}+\frac{x+7}{95}\)
c) (x+2) - (x+3) >0
d)\(\left(x-5\right)\left(x+\frac{7}{3}\right)\ge0\)
Tìm x , y biết : \(\frac{3}{5}x=\frac{2}{3}y\)và x2 - y2 = 38
Tìm x sao cho
a, \(\left|\frac{5}{7}x-4\right|< \frac{2}{7}\)
b, \(\left|\frac{5}{7}x-4\right|>\frac{3}{5}\)
Bài 1 : Tìm x biết :
a, \(\left|\frac{3}{2}x+\frac{1}{2}\right|=\left|4x-1\right|\)
b, \(\left|\frac{5}{4}x-\frac{7}{2}\right|-\left|\frac{5}{8}x+\frac{3}{5}\right|=0\)
c,\(\left|\frac{7}{5}x+\frac{2}{3}\right|=\left|\frac{4}{3}x-\frac{1}{4}\right|\)
Bài 2 : Tìm x biết :
a, | 2x - 5 | = x +1
b, | 3x - 2 | -1 = x
c, | 3x - 7 | = 2x + 1
d, | 2x-1 | +1 = x
Tìm x bt:
a)\(\frac{2}{x+7}=\frac{x+7}{32}\)
b)\(\frac{x-2}{x+5}=\frac{x-5}{x+8}\)
GIÚP MK VỚI:3333
Tìm x \(\frac{7^{x+2}+7^{x+1}+7^x}{57}=\frac{5^{2x}+5^{2x+1}+5^{2x+3}}{131}\)
tìm x biết : \(\frac{7^{x+2}+7^{x+1}+7^x}{57}=\frac{5^{2x}+5^{2x+1}+5^{2x+3}}{131}\)
Tìm x
\(\frac{7^{x+2}+7^{x+1}+7^x}{57}=\frac{5^{2x}+5^{2x+1}+5^{2x+3}}{131}\)
Tìm x biết : \(\frac{7^{x+2}+7^{x+2}+7^x}{57}=\frac{5^{2x}+5^{2x+1}+5^{2x+3}}{131}\)
Tìm X ,Y biết ; \(\frac{X+1}{2}=\frac{2.Y-7}{5}=\frac{X-2.Y+8}{X}=\frac{\left(2.Y-7\right)+\left(X-2.Y+8\right)}{5+X}.\) .;;; Các bạn giúp mình với .