\(x-\frac{3}{2}=3x+\frac{1}{4}\)
\(x-3x=\frac{1}{4}+\frac{3}{2}\)
\(-2x=\frac{7}{4}\)
\(x=\frac{7}{4}:\left(-2\right)\)
\(x=-\frac{7}{8}\)
Tìm x :
\(x-\frac{3}{2}=3x+\frac{1}{4}\)
\(\Leftrightarrow x-3x=\frac{1}{4}+\frac{3}{2}\)
\(\Leftrightarrow1x-3x=\frac{1}{4}+\frac{6}{4}\)
\(\Leftrightarrow-2x=\frac{7}{4}\)
\(\Leftrightarrow x=\frac{7}{4}:\left(-2\right)\)
\(\Leftrightarrow x=\frac{7}{4}.\frac{-1}{2}\)
\(\Leftrightarrow x=-\frac{7}{8}\)