tim x y thuoc z biet (x+y).2=xy
tim x,y thuoc Z biet 25-y^2=9(x-2018)^2
tim x thuoc z sao cho \(x^2+102=y^2\)
tim cac so x,y,z thuoc Q biet rang (x+y):(5-z):(y+z):(y+9)=3:1:2:5
tim x,y thuoc z biet 25-\(y^2\)=8.(x-2009)^2
tim x,y thuoc Z biet
25-y2=8(x-2015)2
Tim x,y thuoc z biet : 3x^2 + 5y^ 2 =108
a, Tim x biet:/x-2/+/3-2x/=2x+1
b, Tim x,y thuoc Z biet:xy+2x-y=5
c, tim x,y,z, biet :2x=3y;4y=5zva 4x-3y+5z=7
tim x;y thuoc Z biet (2*x+5*y+1)*(2|x|+y+x2+x)=105
