8^x-1=1/8=1/8^1=8^(-1)
=>x-1=-1=>x=0
Có: 8^x-1=\(\frac{1}{8^x}\)\(\Rightarrow\)x-1=1
\(\Rightarrow\) x=0
\(8^{x-1}=\frac{1}{8}=8^{-1}\Rightarrow x-1=-1\Rightarrow x=0\)
ta có:8x-1=1/8 =>8x-1=8-1
=>x-1=(-1)=>x=0
Ta có :8x-1 = 1/8
8x-1 = 8-1
x - 1 = - 1 = 0
tim cho mình nha