tim x,y,z thuoc z biet /x/+/y/+/z/=0
Bai1:Tim x thuoc Z biet:
a)7x=14
b)6x-(-5)=17
(x+2) (x-9)=0
tim x thuoc Z biet x*(x-1) > 0
tim x thuoc Z biet (x-7)x(x+3)<0
tim x thuoc Z biet :
(x-1)^2 =(x-3)^4
HELP ME:0!!
tim x, y thuoc z biet (x+7 ) (xy + 1)= 9
tim x thuoc z,biet
(x-5)^2=0
Tim X thuoc Z biet :
(x-3).(x+2)<0
Tim x, y thuoc Z biet : | x-2| + (x-y+1)^2 =0
