Question

tim x thoa man  

x-1\2006+x-10\1997+x-19\1988=3

Answer 1

\(\frac{x-1}{2016}+\frac{x-10}{1997}+\frac{x-19}{1988}=3\)

\(pt\Leftrightarrow\frac{x-1}{2016}-1+\frac{x-10}{1997}-1+\frac{x-19}{1988}-1=0\)

\(\Leftrightarrow\frac{x-2017}{2016}+\frac{x-2017}{1997}+\frac{x-2017}{1988}=0\)

\(\Leftrightarrow\left(x-2017\right)\left(\frac{1}{2016}+\frac{1}{1997}+\frac{1}{1988}\right)=0\)

Dễ thấy: \(\frac{1}{2016}+\frac{1}{1997}+\frac{1}{1988}\ne0\)

\(\Rightarrow x-2017=0\Rightarrow x=2017\)