Câu hỏi của nguyễn thế hoàng

Question

tìm x lớp 6$\dfrac{1}{2}:x+\dfrac{1}{4}:x+\dfrac{1}{8}:x=\dfrac{3}{7}$

Lê Minh Vũ · Accepted Answer

$\dfrac{1}{2}\div x+\dfrac{1}{4}\div x+\dfrac{1}{8}\div x=\dfrac{3}{7}$

$\left(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}\right)\div x=\dfrac{3}{7}$

$\dfrac{7}{8}\div x=\dfrac{3}{7}$

$x=\dfrac{49}{24}$Câu trả lời: $\dfrac{1}{2}\div x+\dfrac{1}{4}\div x+\dfrac{1}{8}\div x=\dfrac{3}{7}$

$\left(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}\right)\div x=\dfrac{3}{7}$

$\dfrac{7}{8}\div x=\dfrac{3}{7}$

$x=\dfrac{49}{24}$

Nguyễn Thị Thương Hoài · Answer

$\dfrac{1}{2}$: $x$ + $\dfrac{1}{4}$: $x$ + $\dfrac{1}{8}$: $x$ = $\dfrac{3}{7}$

($\dfrac{1}{2}$ + $\dfrac{1}{4}$ + $\dfrac{1}{8}$):$x$ = $\dfrac{3}{7}$

($\dfrac{4}{8}$+ $\dfrac{2}{8}$ + $\dfrac{1}{8}$): $x$ = $\dfrac{3}{7}$

$\dfrac{7}{8}$  : $x$  = $\dfrac{3}{7}$

$x$  = $\dfrac{7}{8}$ : $\dfrac{3}{7}$

$x$ =  $\dfrac{49}{24}$Câu trả lời: $\dfrac{1}{2}$: $x$ + $\dfrac{1}{4}$: $x$ + $\dfrac{1}{8}$: $x$ = $\dfrac{3}{7}$

($\dfrac{1}{2}$ + $\dfrac{1}{4}$ + $\dfrac{1}{8}$):$x$ = $\dfrac{3}{7}$

($\dfrac{4}{8}$+ $\dfrac{2}{8}$ + $\dfrac{1}{8}$): $x$ = $\dfrac{3}{7}$

$\dfrac{7}{8}$  : $x$  = $\dfrac{3}{7}$

$x$  = $\dfrac{7}{8}$ : $\dfrac{3}{7}$

$x$ =  $\dfrac{49}{24}$

✎﹏Kim Kim✧❤‿✶🌈(*•.¸♡ţę... · Answer

$\dfrac{1}{2}:x+\dfrac{1}{4}:x+\dfrac{1}{8}:x=\dfrac{3}{7}$

$\Rightarrow\dfrac{1}{2}\cdot\dfrac{1}{x}+\dfrac{1}{4}\cdot\dfrac{1}{x}+\dfrac{1}{8}\cdot x=\dfrac{3}{7}$

$\Rightarrow\dfrac{1}{x}\cdot\left(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}\right)=\dfrac{3}{7}$

$\Rightarrow\dfrac{1}{x}\cdot\dfrac{7}{8}=\dfrac{3}{7}$

$\Rightarrow\dfrac{1}{x}=\dfrac{3}{7}:\dfrac{7}{8}$

$\Rightarrow\dfrac{1}{x}=\dfrac{24}{49}$

$\Rightarrow x=1:\dfrac{24}{49}$