(x+8)3+30=-2
(x+8)3=-32
(x=8)3+30=-2
x3=512+30=-2
x3=542=-2
xog ht bt
\(\left|x\right|-5\frac{3}{7}\left|x\right|-\frac{3}{4}=2\left|x\right|+\left(-\frac{8}{7}\right)\)
Tim x
a) \(\left(19x+2.5^2\right):14=\left(13-8\right)^2-4^2\)
b) \(x+\left(x+1\right)+\left(x+2\right)+...+\left(x+30\right)=1240\)
c) \(|x+7|=20+5.\left(-3\right)\)
Tìm x, biết:
\(\frac{3}{\left(x+2\right)\left(x+5\right)}+\frac{5}{\left(x+5\right)\left(x+10\right)}+\frac{7}{\left(x+10\right)\left(x+17\right)}=\frac{x}{\left(x+2\right)\left(x+17\right)}\left(x\notin-2;-5;-10;-17\right)\)
\(\frac{2}{\left(x-1\right)\left(x-3\right)}+\frac{5}{\left(x-3\right)\left(x-8\right)}+\frac{12}{\left(x-8\right)\left(x-20\right)}-\frac{1}{x-20}=-\frac{3}{4}\)
Với \(x\notin1;3;8;20\)
\(\frac{x+1}{10}+\frac{2+1}{11}\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)
\(\frac{x-10}{30}+\frac{x-14}{43}+\frac{x-5}{95}+\frac{x-148}{8}=0\)
Tìm GTNN
a.\(A=\left|\frac{x}{5}+\frac{23}{2}\right|+\left|y-\frac{14}{3}\right|+2019\)
b. \(B=\left(x-\frac{5}{4}\right)^{20}+\left(y+\frac{4}{3}\right)^{30}-11\)
AI LÀM NHANH TỚ TIM
Tìm x, biết:
a) \(\left|x-24\right|+\left|y+8\right|=1\)
b)\(\left(x-2\right)^{10}+\left|y-2\right|=0\)
c)\(x+\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+30\right)=1240\)
d)\(x+\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+2017+2018=2018\)
Giải thích cụ thể giúp mk nha
Bài 2 : Tìm x , biết :
a, \(\left(19x+2\cdot5^2\right)\text{ : }14=\left(13-8\right)^2-4^2\)
b, \(x+\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+30\right)=1240\)
c, \(11-\left(-53+x\right)=97\)
d, \(-\left(x+84\right)+213=-16\)
e, \(13-12+11+10-9+8-7-6+5-4+3+2-1=x\)
Tim x :
A: \(3\left(x+\frac{1}{2}\right)=8\)
B: \(4x+\frac{1}{2}^3=-7\)
C: \(4\left(x-\frac{1}{2}\right)+\left(-3\right)^2=9\)
GIUP HO MK NHE ..
Tìm số tn biết
770÷[(20x+10)÷x]=35
30-[4 (x-2)+15]=3
\(\left[8X-120\div4\right].3^3=3^6\)
\(\left\{X^2-[8^2-\left(5^2-8.3\right)^3-7.9]^3-4.12\right\}^3=1\)
tim x thuoc z\(^{\left(x+8\right):\left(x+7\right)}\)