Question

Tìm x :

\(\frac{x+1}{65}\)+ \(\frac{x+3}{63}\)=\(\frac{x+5}{61}\)+\(\frac{x+7}{59}\)

Answer 1

\(\frac{x+1}{65}+\frac{x+3}{63}=\frac{x+5}{61}+\frac{x+7}{59}\)

<=>\(\frac{x+1}{65}+\frac{x+3}{63}-\frac{x+5}{61}-\frac{x+7}{59}=0\)

<=>\(\frac{x+1}{65}+1+\frac{x+3}{63}+1-\frac{x+5}{61}-1-\frac{x+7}{59}-1=0\)

<=>\(\frac{x+66}{65}+\frac{x+66}{63}-\frac{x+66}{61}-\frac{x+66}{59}=0\)

<=>\(\left(x+66\right)\left(\frac{1}{65}+\frac{1}{63}-\frac{1}{61}-\frac{1}{59}\right)=0\)

Do \(\frac{1}{65}+\frac{1}{63}-\frac{1}{61}-\frac{1}{59}\ne0\)

=>x+66=0

<=>x=-66

Answer 2

x= 66

nhe sbn

chắc chắn 

thôi bn ạ

mình tính nháp rùi

Answer 3

66

tk nhe

minh hoc roi

xin

Answer 4

66

tk nhe

minh hoc roi

xin

Answer 5

Tìm x :

x+165 + x+363 =x+561 +x+759 

x= 66

chắc chắn 

mình tính nháp rùi

dễ

Answer 6

66 chuẩn luôn

Answer 7

\(\frac{x+1}{65}+\frac{x+3}{63}=\frac{x+5}{61}+\frac{x+7}{59}\)

\(\Leftrightarrow\left(\frac{x+1}{65}+1\right)+\left(\frac{x+1}{63}+1\right)-\left(\frac{x+5}{61}+1\right)-\left(\frac{x+7}{59}+1\right)=0\)

\(\Leftrightarrow\frac{x+66}{65}+\frac{x+66}{63}-\frac{x+66}{61}-\frac{x+66}{59}=9\)

\(\Leftrightarrow\left(x+66\right)\left(\frac{1}{65}+\frac{1}{63}-\frac{1}{61}-\frac{1}{59}\right)=0\)

<=> x+66=0

<=> x=-66

Answer 8

PT trên \(< =>\frac{x+1}{65}+\frac{x+3}{63}-\frac{x+5}{61}-\frac{x+7}{59}=0\)

\(< =>\frac{x+66}{65}+\frac{x+66}{63}-\frac{x+66}{61}-\frac{x+66}{59}=0\)

\(< =>\left(x+66\right).\left(\frac{1}{65}+\frac{1}{63}-\frac{1}{61}-\frac{1}{59}\right)=0\)

Do \(\frac{1}{65}+\frac{1}{63}-\frac{1}{61}-\frac{1}{59}\ne0\)

\(< =>x+66=0< =>x=-66\)

Answer 9

66 nha ban