\(\dfrac{x}{x+1}< -1\)
\(\Leftrightarrow\dfrac{x}{x+1}+1< 0\)
\(\Leftrightarrow\dfrac{x+x+1}{x+1}< 0\)
\(\Leftrightarrow2x+1< 0\)
\(\Leftrightarrow2x< -1\)
\(\Leftrightarrow x< -\dfrac{1}{2}\)
Vậy \(x< -\dfrac{1}{2}\) thì \(A< -1\)
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