Vì |x| \(\le\)3
=> x \(\in\){-3;-2;-1;0;1;2;3}
Vậy x \(\in\){-3;-2;-1;0;1;2;3}
Vì |x| \(\le\)3
=> x \(\in\){-3;-2;-1;0;1;2;3}
Vậy x \(\in\){-3;-2;-1;0;1;2;3}
Tim x biet:
A. (x-3/4).(3x+1/2)lon hon hoac bang 0
B. (2x+1).(4x+3)be hon hoac bang 0
tim x,y biet |x-3|^2014+|6+2y|^2015 be hon hoac bang 0
tim so tn a be thua hoac bang 200 biet rang khi chia a cho stn b thi duoc thuong la 41 va du 35
Ting tong cac so nguyen x biet :
a ) -18 be hon hoac bang x be hon hoac bang 17
b) Gia tri tuyet doi cua x be hon hoac bang 3.
Giup Minh Voi !
a)
tinh (-10)+12+(-14)+16+(-18)+20+(-24)+26+(-2015)+2017
b) tinh
455+(-311)+3789+(-144)
c) tim tong cac so nguyen x biet
a) -4 <x be hon hoac bang 4
b) -7 < hoac bang x < hoac bang 8
c) -9 < x < hoac bang 5
1) Tim cac so tu nhien biet 1950 nho hon hoac bang X nho hon hoac bang 2015
va X chia cho 4 du 1 ; chiacho 25 du 3
tim x biet:|x| nho hon hoac bang 5
Tim tong cac so nguyen x biet -10<hoac bang x < 10
Tim so nguyen x, biet:
( x -5) .(x -10) lon hon hoac bang 0