\(\left|x\right|+2018.\frac{1}{2}=2019,25\)
\(\Rightarrow\left|x\right|+1009=2019,25\)
\(\Rightarrow\left|x\right|=2019,25-1009\)
\(\Rightarrow\left|x\right|=1010,25\)
\(\Rightarrow\orbr{\begin{cases}x=1010,25\\x=-1010,25\end{cases}}\)
Vậy \(x\in\left\{1010,25;-1010,25\right\}.\)
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