LQ

Tìm x biết:(x+1)+(x+2)+(x+3)+...+(x+2017)=0

LN
10 tháng 2 2017 lúc 19:38

Ta có:(x+1)+(x+2)+(x+3)+...(x+2017)=0

=x+1+x+2+x+3+...+x+2017=0

=x+x+x+...+x+1+2+3+...+2017=0

=2017x+(1+2+3+...+2017)

=2017x+1008*2018+2017=0

=2017x+2034144+2017=0

=2017x+2036161=0

2017x=-2036161

x=-1009,499752

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