Question

Tìm  x , biết:

(x+1)+(x+2)+(x+3)+...+(x+100) = 6050

Answer 1

(x+1)+(x+2)+(x+3)+...+(x+100) = 6050

=> x+1+x+2+x+3+...+x+100  = 6050

=> ( x + x + x ... + x ) + ( 1 + 2 + 3 +  ... + 100 ) = 6050

=> 100x + 5050 = 6050

=> 100x = 6050 - 5050 = 1000

=> x = 1000 : 100 = 10

Vậy x = 10

Answer 2

(x+1)+(x+2)+(x+3)+...+(x+100) = 6050

=> (x+x+x+...+x)+(1+2+3+...+100) = 6050

=> 100x + 5050 = 6050

100x = 6050 - 5050

100x = 1000

x = 1000 : 100

x = 10