\(\Rightarrow x+\frac{1}{2}+x+\frac{1}{3}+x+\frac{1}{4}+x+\frac{1}{5}-x+\frac{1}{6}=0\)
\(\Rightarrow3x+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}\)
k cho minh
\(x+\frac{1}{2}+x+\frac{1}{3}+x+\frac{1}{4}+x+\frac{1}{5}=x+\frac{1}{6}\)
\(\Leftrightarrow x+\frac{1}{2}+x+\frac{1}{3}+x+\frac{1}{4}+x+\frac{1}{5}-x-\frac{1}{6}=0\)
\(\Leftrightarrow3x+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}-\frac{1}{6}=0\)
Tính ra nhé !
\(x+\frac{1}{2}+x+\frac{1}{3}+x+\frac{1}{4}+x+\frac{1}{5}=x+\frac{1}{6}\)
\(\left(x+x+x+x\right)+\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}\right)=x+\frac{1}{6}\)
\(\Rightarrow4x+\frac{77}{60}=x+\frac{1}{6}\)
\(\Rightarrow3x=\frac{1}{6}-\frac{77}{60}\)
\(\Rightarrow3x=-\frac{67}{60}\)
\(\Rightarrow x=-\frac{67}{60}\div3=\frac{-67}{60.3}=-\frac{67}{180}\)
Vậy x = .........
\(x+\frac{1}{2}+x+\frac{1}{3}+x+\frac{1}{4}+x+\frac{1}{5}=x+\frac{1}{6}\)
\(\Leftrightarrow\left(x+x+x+x\right)+\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}\right)=x+\frac{1}{6}\)
\(\Leftrightarrow\left(4x\right)+\frac{77}{60}=x+\frac{1}{6}\)
\(\Leftrightarrow3x=\frac{1}{6}-\frac{77}{60}\)
\(\Leftrightarrow3x=-\frac{67}{60}\)
\(\Leftrightarrow x=-\frac{67}{60}\div3\)
\(\Leftrightarrow x=-\frac{67}{180}\)
x + 1/2 + x + 1/3 + x + 1/4 + x + 1/5 = x + 1/6
(x + x + x + x) + (1/2 + 1/3 + 1/4 + 1/5) = x + 1/6
x * 4 + 77/60 = x + 1/6
x * 4 + 77/60 - x = 1/6
x * 3 + 77/60 = 1/6
x * 3 = - 67/60
x = - 67/60 : 3
x = 67/180
Chúc bạn hok tốt nha!