Question

tim x biet

|x-3|=2x-1

 

Answer 1

TH1:x-3=2x-1

=>-3+1=2x-x

=>-2=x

=>x=-2

TH2:x-3=-(2x-1)

=>x-3=-2x+1

=>-3-1=-2x-x

=>-4=-3x

=>4=3x

=>x=4:3

=>x=4/3

Vậy x\(\in\){-2,4/3} thỏa mãn

Answer 2

/x-3/=2x-1

=>x-3=2x-1 hoặc -(2x-1)

TH1

x-3=2x-1

x=2x+2

-x=2

=>x=-2

TH2

x-3=-(2x-1)

x-3=-2x+1

x=-2x+4

x-(-2x)=4

3x=4

x=4/3

Vậy x thuộc [-2;4/3}