Các câu hỏi tương tự
\(\frac{3}{4}.\frac{4}{6}.\frac{5}{8}...\frac{2010}{4018}=1005.16^{1-x}\)
Tìm số hữu tỉ x,biết : \frac{x+6}{2010}+\frac{x+5}{2009}=\frac{x+4}{2008}+\frac{x+4}{2007}
1) Tìm x Biết
x-\(\frac{1}{3}\)=\(\frac{3}{4}\)
\(\frac{-1,25}{x}=\frac{1}{-8}\)
\(4\frac{1}{3}\div\frac{x}{4}=6:0,3\)
\((x-\frac{4}{9})^2=\frac{1}{4}\)
\(9^x\times81^x=3^{2010}\)
Tìm x biết
a)\(\frac{x+4}{2009}+\frac{x+3}{2010}=\frac{x+2}{2011}+\frac{x+1}{2012}\)
b)\(\left(\frac{1}{4}x-1\right)\)+\(\left(\frac{5}{6}x-2\right)-\left(\frac{3}{8}x+5\right)=3,5\)
CMR: \(\frac{1}{2^2}-\frac{1}{2^4}+\frac{1}{2^6}-...+\frac{1}{2^{2002}}-\frac{1}{2^{2004}}< 0,2\)
tìm x biết:
\(|x-\frac{1}{3}|=|\left(-3,2\right)+\frac{2}{5}|\)
\(\frac{x-1}{2011}+\frac{x-2}{2010}-\frac{x-3}{2009}=\frac{x-4}{2008}\)
tìm x biết:
\(\frac{x-1}{2011}+\frac{x-2}{2010}+\frac{x-3}{2009}=\frac{x-4}{2008}\)
Tìm x biết
\(\frac{x+1}{2013}+\frac{x+2}{2012}=\frac{x+3}{2011}+\frac{x+4}{2010}\)
Tìm x biết
\(|x+\frac{1}{3}|+\frac{4}{5}=|\left(-3,2\right)+\frac{2}{5}|+\left(27-\frac{3}{5}\right)\left(27-\frac{3^2}{6}\right)\left(27-\frac{3^3}{7}\right)...\left(27-\frac{3^{2010}}{2014}\right)\)
Tìm x biết :
\(\frac{x-1}{2012}+\frac{x-2}{2011}+\frac{x-3}{2010}+\frac{x-4}{2009}+\frac{x-2021}{2}=0\)