\(\frac{1+2y}{8}=\frac{1+4y}{24}=\frac{1+6y}{6x}=\frac{2\left(1+2y\right)-\left(1+4y\right)}{2.8-24}=\frac{1}{-8}\)
=> \(\frac{1+2y}{8}=\frac{1}{-8}\) => 1+2y = -1 => y = -1
\(\frac{1+6y}{6x}=\frac{1}{-8}\) => \(\frac{1+6.\left(-1\right)}{6x}=\frac{1}{-8}\)
=> \(\frac{-5}{6x}=\frac{1}{-8}\) => x = (-5).(-8)/6 = 20/3
\(\frac{1+2y}{18}=\frac{1+4y}{24}=\frac{1+6y}{6x}\)
tim x va y.
tim so huu ti x biet
\(\frac{x}{y^2}\)=2 va \(\frac{x}{y}\)=16 (voi y khac 0)
\(\frac{1+2y}{18}\)=\(\frac{1+4y}{24}\)=\(\frac{1+6y}{6x}\)
Tim gia tri nho nhat
A=/x-2010/+/x-2011/
B=/x-1/+/x-2/+/x-3/+2011
C=5\(x^2\)+20x+2010
cac ban giai va cach trinh bay nhe
minh kich dung cho
giai giup minh voi
Tìm x : \(\frac{1+2y}{18}=\frac{1+4y}{24}=\frac{1+6y}{6x}\)
\(\frac{1+2y}{18}=\frac{1+4y}{24}=\frac{1+6y}{6x}\)
tìm X
Tìm x biết \(\frac{1+2y}{18}=\frac{1+4y}{24}=\frac{1+6y}{6x}\)
Tìm x biết \(\frac{1+2y}{18}=\frac{1+4y}{24}=\frac{1+6y}{6x}\)
tìm x
\(\frac{1+2y}{18}=\frac{1+4y}{24}+\frac{1+6y}{6x}\)
Tìm x biết rằng ; \(\frac{1+2y}{18}=\frac{1+4y}{24}=\frac{1+6y}{6x}\)
