Question

Tìm x biết

\(\dfrac{2x-x}{32}=\dfrac{2}{2-x}\)

Answer 1

\(ĐXKĐ:x\ne2\)

\(\dfrac{2-x}{32}=\dfrac{2}{2-x}\\ \Leftrightarrow\left(2-x\right)^2=64\\ \Rightarrow\left[{}\begin{matrix}2-x=-8\\2-x=8\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=10\left(tm\right)\\x=-6\left(tm\right)\end{matrix}\right.\)

Answer 2

\(\dfrac{2x-x}{32}=\dfrac{2}{2-x}\\ \Rightarrow\dfrac{x}{32}=\dfrac{2}{2-x}\\ \Rightarrow x\left(2-x\right)=64\\ \Rightarrow-x^2+2x-64=0\\ \Rightarrow x^2-2x+64=0\\ \Rightarrow\left(x^2-2x+1\right)+63=0\\ \Rightarrow\left(x-1\right)^2+63=0\)

Vì \(\left(x-1\right)^2\ge0;63>0\Rightarrow\left(x-1\right)^2+63>0\)

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