a) \(\frac{x}{x+1}=\frac{x+5}{x+7}\)
\(=>x\left(x+7\right)=\left(x+1\right).\left(x+5\right)\)
\(=>x^2+7x=x^2+6x+5\)
\(=>x^2+7x-x^2-6x-5=0\)
\(=>x-5=0\)
\(=>x=5\)
vay \(x=5\)
b) \(\frac{x+7}{x+4}=\frac{x-1}{x-2}\)
\(=>\left(x+7\right)\left(x-2\right)=\left(x+4\right)\left(x-1\right)\)
\(=>x^2+5x-14=x^2+3x-4\)
\(=>x^2+5x-14-x^2-3x+4=0\)
\(=>2x-10=0\)
\(=>2\left(x-5\right)=0\)
\(=>x-5=0\)
\(=>x=5\)
vay \(x=5\)
c) \(\frac{x+2}{x-2}=\frac{x-3}{x+3}\)
\(=>\left(x+2\right)\left(x+3\right)=\left(x-2\right)\left(x-3\right)\)
\(=>x^2+5x+6=x^2-7x+6\)
\(=>x^2+5x+6-x^2+7x-6=0\)
\(=>12x=0\)
\(=>x=0\)
vay \(x=0\)
đáp số là 0 , đúng thì cho mình xin đúng nhé cảm ơn