a) \(7x-10=5x-6\)
\(7x-5x=-6+10\)
\(2x=4\)
\(x=2\)
b) \(3x\left(x-2\right)+x-2=0\)
\(\left(x-2\right)\left(3x+1\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-2=0\\3x+1=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=2\\x=-\frac{1}{3}\end{cases}}\)
c) \(2x^2+7x-4=0\)
\(2x^2-x+8x-4=0\)
\(x\left(2x-1\right)+2\left(2x-1\right)=0\)
\(\left(2x-1\right)\left(x+2\right)=0\)
\(\Rightarrow\orbr{\begin{cases}2x-1=0\\x+2=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{1}{2}\\x=-2\end{cases}}\)
7x-10=5x-6<=>7x-5x=-6+10<=>2x=4=>x=2
3x(x-2)+x-2=0<=>(x-2)(3x+1)=0<=>x-2=0=>x=2 HAY 3x+1=0=>x=-1/3
2x2+7x-4=0.
Câu cuối xem có lộn đề không nha bạn ơi!!!
a) 7x - 10 = 5x - 6
<=> 7x - 5x = -6 + 10
<=> 2x = 4
<=> x = 2
b) 3x( x - 2 ) + x - 2 = 0
<=> 3x( x - 2 ) + 1( x - 2 ) = 0
<=> ( x - 2 )( 3x + 1 ) = 0
<=> \(\orbr{\begin{cases}x-2=0\\3x+1=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=2\\x=-\frac{1}{3}\end{cases}}\)
c) 2x2 + 7x - 4 = 0
<=> 2x2 + 8x - x - 4 = 0
<=> 2x( x + 4 ) - 1( x + 4 ) = 0
<=> ( x + 4 )( 2x - 1 ) = 0
<=> \(\orbr{\begin{cases}x+4=0\\2x-1=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=-4\\x=\frac{1}{2}\end{cases}}\)