\(4x\left(12x-9\right)-8x\left(6x-5\right)=1\)
\(\Leftrightarrow48x^2-36x-48x^2+40x=1\)
\(\Leftrightarrow4x=1\Leftrightarrow x=\dfrac{1}{4}\)
tìm x biết 4x^2-4x=-1
8x^3+12x^2+6x+1=0
tìm x biết: \(\text{8x^3-12x^2+6x+1-(4x^2-1)=0}\)
Tìm x ,biết
(4x-1)3+(3-4x)(9+12x+16x2)=(8x-1)(8x+1)-(3x-5)
Tìm x:
(7x-9)(8x+5)(-12x+5)(4x-1)=(3x-5)(8x+7)
Tìm x: (4x-1)^3+(3-4x).(9+12x+16x^2)=(8x-1).(8x+1)-(3x-5)
Tìm x, biết:
a) 4x^2 - 4x = -1
b) 8x^3 + 12x^2 + 6x +1 = 0
Giúp mình với =)))))
Tìm x
(4x-1)^3+(3-4x)(9+12x+16x^2)=(8x-1)(8x+1)-(3x-5)
tìm x
a(14x^3+12x^2-14x):2x=(x+2)(3x-4)
b(4x−5)(6x+1)−(8x+3)(3x−4)=15
Tìm x
(4x-1)^3+(3-4x)(9+12x+16x^2)=(8x-1)(8x+1)-(3x-5)
