\(\left(4x-2\right)\left(x+5\right)=0\)
\(\Rightarrow\orbr{\begin{cases}4x-2=0\\x+5=0\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{1}{2}\\x=-5\end{cases}}}\)
\(\left(4x-2\right)\left(x+5\right)=0\)
\(\Rightarrow\orbr{\begin{cases}4x-2=0\\x+5=0\end{cases}}\Rightarrow\orbr{\begin{cases}4x=2\\x=-5\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{1}{2}\\x=-5\end{cases}}\)
Vậy \(x\in\left\{-5;\frac{1}{2}\right\}\)