Question

Tìm x, biết:

\(4\left(x+1\right)^2+\left(2x-1\right)^2-8\left(x-1\right)\left(x+1\right)=11\)

Answer 1

\(49\left(x^2+2x+1\right)+\left(4x^2-4x+1\right)-8\left(x^2-1\right)=11\)

\(4x^2+8x+4+4x^2-4x+1-8x^2+8-11=0\)

\(4x+2=0\)

\(4x=2\)

\(x=-\frac{1}{2}\)

Answer 2

<=>4(x²+2x+1)+4x²-4x+1-8x²+8-11=0

<=>4x²+8x+4+4x²-4x+1-8x²+8-11=0

<=>4x+2=0

<=>2(2x+1)=0

<=>2x+1=0

<=>x=-1/2

Answer 3

XL mik nhầm

\(=\frac{1}{2}\)

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