\(3x\left(\frac{4}{3}x+1\right)-4x\left(x-2\right)=10\)
\(\Rightarrow4x^2+3x-4x^2+8x=10\)
\(\Rightarrow\left(4x^2-4x^2\right)+\left(3x+8x\right)=10\Rightarrow11x=10\Rightarrow x=\frac{10}{11}\)
Vậy x=10/11
\(3x\left(\frac{4}{3}x+1\right)-4x\left(x-2\right)=10\)
\(\Rightarrow4x^2+3x-4x^2+8x=10\)
\(\Rightarrow\left(4x^2-4x^2\right)+\left(3x+8x\right)=10\Rightarrow11x=10\Rightarrow x=\frac{10}{11}\)
Vậy x=10/11
Bài 1 : Tìm x biết :
a, \(\left|\frac{3}{2}x+\frac{1}{2}\right|=\left|4x-1\right|\)
b, \(\left|\frac{5}{4}x-\frac{7}{2}\right|-\left|\frac{5}{8}x+\frac{3}{5}\right|=0\)
c,\(\left|\frac{7}{5}x+\frac{2}{3}\right|=\left|\frac{4}{3}x-\frac{1}{4}\right|\)
Bài 2 : Tìm x biết :
a, | 2x - 5 | = x +1
b, | 3x - 2 | -1 = x
c, | 3x - 7 | = 2x + 1
d, | 2x-1 | +1 = x
2/ Tìm x biết:
a,\(\frac{3x}{5}-\frac{7}{10}x-\frac{x-3}{2}=0\)
b,\(\left(4x+3\right)^2=\frac{2}{3}:6\)
c,\(\left|3x+\frac{1}{2}\right|-2=\sqrt{\left(-\frac{3}{2}\right)^2}\)
tìm x biết
a,\( |2-\frac{3}{2}x|-4=x+2\)
b,\(\left(4x-1\right)^{30}=\left(4x-1\right)^{20}\)
c,\(2.3^x-405=3^{x-1}\)
d.\(\left(\frac{1}{81}\right)^x.27^{2.x}=\left(-9\right)^4\)
e,\(\frac{x+1}{65}+\frac{x+3}{63}=\frac{x+5}{61}+\frac{x+7}{59}\)
g,\(\left(\frac{1}{2}\right)^{3x-1}=\frac{1}{32}\)
h,\(|3x-5|=|\frac{1}{2}x+3|\)
i,\(\left(\frac{3}{4}-x\right)^3=\frac{1}{64}\)
Tìm x:
|5x-3|-3x=7
|x-3|+|x-5|-4x=-28
\(\left|x+2\right|+\left|x+\frac{3}{5}\right|+\left|x+\frac{1}{2}\right|=4x\)
\(\left|2x-1\right|+\left(4x^2-1\right)^2=0\)
tìm x biết:
a)\(-4\left(2x+\frac{1}{2}\right)-2.\left(3,2x-5\right)=2,1\left(2-4x\right)\)
b)\(\frac{\left(x-2\right)\left(3-x\right)}{5+x}\le0\)
c) \(\left(-3,5x+0,75\right)+\left(\frac{1}{2}x-4\right)=-3x+7\)
Tìm x, biết:
a, 2x-10-[3x-14-(4-5x)-2x] = 2
b,\(\left(\frac{1}{4}x-1\right)+\left(\frac{5}{6}x-2\right)-\left(\frac{3}{8}x+1\right)=4,5\)
Tìm x biết:
\(\frac{-1}{2}\times\left(3x-1\right)+\frac{3}{4}\left(3-2x\right)=-3\times\left(\frac{x}{2}-1\right)-\left(\frac{4}{5}\right)^{-1}\)
Tìm x biết
a, \(|5x-3|-3x=12\)
b, \(|x^2-2x-4|+4=4x\)
c, \(\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)\left(1-\frac{1}{4}\right)...\left(1-\frac{1}{100}\right)=|x-1\frac{99}{100}|\)
tìm x
\(\frac{1}{3}.\left(2-3x\right)-\frac{1}{7}.\left(4x-2\right)+\frac{1}{2}.\left(x-3\right)=1\)