Question

tim x biet:

(2x-3)² - (x+5)²=0

Answer 1

(2x - 3)² - (x + 5)² = 0

=> (2x - 3 - x - 5).(2x - 3 + x + 5) = 0

=> (x - 8).(3x + 2) = 0

=> \(\orbr{\begin{cases}x-8=0\\3x+2=0\end{cases}}\)=> \(\orbr{\begin{cases}x=8\\3x=-2\end{cases}}\)=> \(\orbr{\begin{cases}x=8\\x=\frac{-2}{3}\end{cases}}\)

Vậy \(x\in\left\{8;\frac{-2}{3}\right\}\)