tính x biết: 1/5.8 + 1/8.11+1/11.14+ ....... +1/x(x+3)= 1 1991/1993
Tìm x, biết:
a) 1/5.8 + 1/8.11 + 1/11.14 + ... + 1/x.(x+3)= 101/1540
b) 1+ 1/3 + 1/6 + 1/10 +...+ 1/x.(x+1):2 = \(1\frac{1991}{1993}\)
tìm x biết
1/5.8+1/8.11+1/11.14+...+1/x(x+3)=101/15401+1/3+1/6+1/10+...+1/x(x+1):2=1 1991/1993tìm x :
a, 1/5.8+1/8.11+11/11.14+...+1/x.(x+3)=101/1540
b, 1+1/3+1/6+1/10+...+1/x.(x+1):2=1 và 1991/1993
Tìm x, biết:
a) 1/5.8 + 1/8.11 + 1/11.14 + ... + 1/x.(x+3)= 101/1540
b) 1+ 1/3 + 1/6 + 1/10 +...+ 1/x.(x+1):2 = \(1\frac{1991}{1993}\)
Tìm x,biết rằng:
a)1/5.8+1/8.11+1/11.14+...1/x(x+3)=101/1540
b)1+1/3+1/6+1/10+...+1/x(x+1):2=1 1991/1993
*1 1991/1993 là hỗn số nha
Giup minh voi!
Tim x:
a) 1/5.8 + 1/8.11 + 1/11.14 +........+ 1/x(x+3) = 101/1540
b) 1 + 1/3 + 1/6+ 1/10+......+ 1/x(x+1):2 = hon so 1 1991/1993
Ai nhanh nhat dung nhat tick lun!(Nho ghi cach giai ro rang)
Tìm x, biết rằng:
a)\(\frac{1}{5.8}+\frac{1}{8.11}+\frac{1}{11.14}+...+\frac{1}{x\left(x+3\right)}=\frac{101}{1540}\)
b)\(1+\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{1}{x\left(x+1\right):2}=1\frac{1991}{1993}\)
Tìm x, biết :
a, \(\frac{1}{5.8}+\frac{1}{8.11}+\frac{1}{11.14}+...+\frac{1}{x.\left(x+3\right)}=\frac{101}{1540}\)
b, \(1+\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{1}{x.\left(x+1\right):2}=1\frac{1991}{1993}\)
