x^3 - 3x^2 + 3x - 1 = 0
( x- 1)^3 = 0
=> x -1 = 0
=> x = 1
x^3 - 3x^2 + 3x - 1 = 0
( x- 1)^3 = 0
=> x -1 = 0
=> x = 1
tim x biet x^2+3x+1=0
tim x biet:
( x^2-4x+16 )( x+4 )-x ( x+1 )(x+2)+3x^2=0
(8x+2)(1-3x)+(6x-1)(4x-10)=-50
tim x biet
16x^3 - 12x^2 + 3x - 7 = 0
tim x biet
a/(3x-5)(2x-1)-(x+2)(6x-1)=0
b/ (3x-5)(3x+2)-(3x-1)2=-5
c/(3x+2)(x-5)=3(x-1)2-2
d/ (x+1)2/3 - (x-2)2/2 = 2x+1/2 (x-3)2/6
g/49x2=(3x+2)2
h/(3x-4)2-(2x-2)2-3(x-2)(2x-1)=0
i/ (x-2)(x2-2x+4)-x(x2+2)=15
k/ 6x2-7x-3=0
m/(x+5)(x-3)+x2-25=0
e/ x3+3x2=4x+12
f/ (6x+7)2(3x+4)(x+1)=6
Tim x, biet:
a)(x-3)^3-(x-3)(x^2+3x+9)+9(x-1)^2=15
b)(x^2-2)^2+4(x-1)^2-4(x^2-2)(x-1)=0
Giup minh voi!
tim x biet 3x^2-5x+2=0
tim x biet (x-2)^3 -(x-3)(x^2+3x+9)+6(x+1)^2
Tim x biet
\(x^4-2x^3-2x^2+3x+2=0\)
TIM X , BIET ; 3x(x-2)-x+2=0 Lam nhanh ho minh nghe