(x+2)+(x+4)+(x+6)+...+(x+100)=2700
(x+x+x+...+x)+(2+4+6+...+100)=2700
50x+2550=2700
50x=150
x=3
(x+2)+(x+4)+(x+6)+...+(x+100)=2700
(x+x+...+x)+(2+4+6+...+100)=2700
50x+[(100+2):2x50] =2700
50x+2550 =2700
50x =2700-2550
50x =150
x =150:50 = 3
Vậy x=3