Các câu hỏi tương tự
Tìm x biết \(\frac{x-23}{24}+\frac{x-23}{25}=\frac{x-23}{26}+\frac{x-23}{27}\)
a) frac{x-23}{24}+frac{x-23}{25}frac{x-23}{26}+frac{x-23}{27}Leftrightarrowfrac{x-23}{24}+frac{x-23}{25}-frac{x-23}{26}-frac{x-23}{27}0Leftrightarrowleft(x-23right)left(frac{1}{24}+frac{1}{25}-frac{1}{26}-frac{1}{27}right)0Leftrightarrow x-230( vì frac{1}{24}+frac{1}{25}-frac{1}{26}-frac{1}{27}ne0)Leftrightarrow x23Vậy nghiệm của pt x23
Đọc tiếp
a) \(\frac{x-23}{24}+\frac{x-23}{25}=\frac{x-23}{26}+\frac{x-23}{27}\)
\(\Leftrightarrow\frac{x-23}{24}+\frac{x-23}{25}-\frac{x-23}{26}-\frac{x-23}{27}=0\)
\(\Leftrightarrow\left(x-23\right)\left(\frac{1}{24}+\frac{1}{25}-\frac{1}{26}-\frac{1}{27}\right)=0\)
\(\Leftrightarrow x-23=0\)( vì \(\frac{1}{24}+\frac{1}{25}-\frac{1}{26}-\frac{1}{27}\ne0\))
\(\Leftrightarrow x=23\)
Vậy nghiệm của pt x=23
\(\dfrac{x-23}{24}\)+\(\dfrac{x-23}{25}\)=\(\dfrac{x-23}{26}\)+\(\dfrac{x-23}{27}\)
Giải phương trình x - 2 3 - x - 2 4 + x - 2 5 = 0
TH
2 tháng 3 2020 lúc 18:47
tìm x biết
\(\frac{\left(24-x\right)^2+\left(24-x\right)\left(x-25\right)+\left(x-25\right)^2}{\left(24-x\right)^2-\left(24-x\right)\left(x-25\right)+\left(x-25\right)^2}=\frac{19}{49}\)
giải phương trình sau:
\(x = {x-25 \over 25} + {x-26 \over 24} + {x-27 \over 23} + {x-26 \over 22} +{x-17 \over 30}\)
giup minh phan tich da thuc thanh nhan tu 1)x^2+4x+32)x^2-4x+33)x^2-x-54)x^2+4x-55)-x^2-x+66)x^2+7x+107)-x^2-3x+108)x^2+7x+129)x^2+4x+310)(x^2-2x+63)11)x^2+10x+2412)-x^2-4x+2113)2x^2+11x+1214)x^2-x+3015)x^2+11x+3016)2x^2+5x-1217)x^2-5x-1418)2x^2+9x+919)x^2+x-7220)-2x^2-15x+2721)x^2-x-1222)-x^2+x+1523)-x^2+5x+1424)x^2-7x-18lam on !!!!!!!!!!!!!!!!!!!!!!!.....!
Đọc tiếp
giup minh phan tich da thuc thanh nhan tu
1)x^2+4x+3
2)x^2-4x+3
3)x^2-x-5
4)x^2+4x-5
5)-x^2-x+6
6)x^2+7x+10
7)-x^2-3x+10
8)x^2+7x+12
9)x^2+4x+3
10)(x^2-2x+63)
11)x^2+10x+24
12)-x^2-4x+21
13)2x^2+11x+12
14)x^2-x+30
15)x^2+11x+30
16)2x^2+5x-12
17)x^2-5x-14
18)2x^2+9x+9
19)x^2+x-72
20)-2x^2-15x+27
21)x^2-x-12
22)-x^2+x+15
23)-x^2+5x+14
24)x^2-7x-18
lam on !!!!!!!!!!!!!!!!!!!!!!!.....!
\(\frac{x+22}{1996}+\frac{x+23}{1995}+\frac{x+24}{1994}+\frac{x+25}{1993}=4\)
Ai giups mik v
(x - 2)2/3 - (2x - 3)(x + 3)/8 + (x - 4)2/6 =0 x3 - (x - 1)3/(4x + 3)(x - 5) = 7x - 1/4x + 3x - 23/24 + x - 23/25 = x - 23/26201 - x/99 + 203 - x/97 +205 - x/95 +3 =0
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