\(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}-\frac{x+1}{13}-\frac{x+1}{14}=0\)
\(\left(x+1\right)\left(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\right)=0\)
=> x + 1 = 0 ( vì 1/10 + 1/11 + 1/12 - 1/13 - 1/14 khac 0 )
=> x = -1
tìm x biết : x+1/10 + x+1/11 + x+1/12 - x+1/13 + x+1/14 = 0
Tìm x biết (x+1)/10 + (x+1) /11 + (x+1)/12 = (x+1)/13 + (x+1)/14
tìm x biết : x+1/10 + x+1/11 + x+1/12 - x+1/13 - x+1/14 = 0
tìm x thuộc Q biết: x+1/10 + x+1/11 + x+1/12 = x+1/13 = x+1/14
Tìm x biết:
x-1/10+x-1/11+x-1/12=x-1/13+x-1/14+x-1/15
tìm số hữu tỉ x biết x+1/10 + x+1/11 + x+1/12 = x+1/13 + x+1/14
GIÚP MINK VS THANK NHÌU
TÌM X
A, 11/12-(5/42-X)=(15/28-11/12)
B,X+1/10+X+1/11+X+1/12=X+1/13+X+1/14
Tìm x, biết: x+1/10 + x+1/11 + x+1/12 = x+1/13 + x+1/14
Tìm x , biết : \(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)