Tuyển Cộng tác viên Hoc24 nhiệm kì 26 tại đây: https://forms.gle/dK3zGK3LHFrgvTkJ6
Tim x biet: x+1/1974+x+2/1973+x+3/1972=-3
Tìm x, biết\(\frac{x+1}{1974}+\frac{x+2}{1973}+\frac{x+3}{1972}=-3\)
Tìm x:
\(\frac{x+1}{1974}+\frac{x+2}{1973}+\frac{x+3}{1972}=-3\)
\(\frac{x+1}{1974}+\frac{x+2}{1973}+\frac{x+3}{1972}=-3\)
\(\frac{x+5}{2005}+\frac{x+6}{2004}+\frac{x+7}{2003}=-3\)
TÌM X
Tìm x thuộc Q, biết:
a) (x-4).(x+1/3)>0
b) x+1/1974 + x+2/1973 + x+3/1974 = -3
Tìm x biết \(\frac{x+1}{1074}+\)\(\frac{x+2}{1974}\)\(+\frac{x+3}{1972}=3\)
x-29/1970+x-27/1972+x-25/1974=x-1970/29+x-1972/27
tinh A/B, biet
A=1/2*32+1/3*33+1/4*34+...+1/n*(n+30)+...+1/1973*2003
B=1/2*1974+1/3*1975+1/4*1976+...+1/n*(n+1972)+...+1/31*2003.
B1: Tìm x
a,\(\frac{2}{7}x\)-\(\frac{1}{3}x\) =\(\frac{5}{21}\)
b, \(\frac{x+1}{1974}\)+ \(\frac{x+2}{1973}\)+ \(\frac{x+3}{1972}\)= (-3)
B2: Tính
\(\frac{-9}{7}\)- \(\frac{5}{13}\)\(\frac{-39}{25}\)+ \(\frac{-1}{42}\)x \(\frac{-5}{6}\)
Mọi người giúp mình với ạ. Mình cảm ơn trước nhé ^_^
