=> ( x-2001/2 + ) + ( x-2002/3 + 1 ) = ( x-2003/4 + 1 ) + ( x-2004/5 + 1 )
=> x-1999/2 + x-1999/3 = x-1999/4 + x-1999/5
=> x-1999/2 + x-1999/3 - x-1999/4 - x-1999/5 = 0
=> (x-1999).(1/2+1/3-1/4-1/5) = 0
=> x-1999=0 ( vì 1/2+1/3-1/4-1/5 > 0 )
=> x = 1999
Vậy x = 1999
Tk mk nha