Question

tìm x biết (x-1)^2016=(1-x)^2018

Answer 1

(x - 1)²⁰¹⁶ = (1 - x)²⁰¹⁸

=> (x - 1)²⁰¹⁶ + (x - 1)²⁰¹⁸ = 0

=> (x - 1)²⁰¹⁶ + (x - 1)²⁰¹⁶.(x - 1)² = 0

=> (x - 1)²⁰¹⁶.[1 + (x - 1)²] = 0

\(\Rightarrow\orbr{\begin{cases}\left(x-1\right)^{2016}=0\\1+\left(x-1\right)^2=0\end{cases}\Rightarrow\orbr{\begin{cases}x-1=0\\\left(x-1\right)^2=-1\end{cases}}}\)

\(\Rightarrow\orbr{\begin{cases}x=1\\x-1=-1\end{cases}\Rightarrow\orbr{\begin{cases}x=1\\x=0\end{cases}}}\)

Answer 2

ST sai rồi nếu \(\left(x-1\right)^{2016}=\left(1-x\right)^{2018}\)

Thì \(\left(x-1\right)^{2016}-\left(1-x\right)^{2018}=0\)