Question

Tìm x biết :

( x + 1 ) + ( x + 2 ) + ... + ( x + 2017 ) = 0

 

Answer 1

\(\left(x+1\right)+\left(x+2\right)+...+\left(x+2017\right)=0\)

\(\Leftrightarrow\left(x+x+...+x\right)+\left(1+2+...+2017\right)=0\)( có 2017 số x )

\(\Leftrightarrow2017x+\frac{\left(2017+1\right)\times2017}{2}=0\)

\(\Leftrightarrow2017x+2035153=0\)

\(\Leftrightarrow2017x=0-2035153\)

\(\Leftrightarrow2017x=-2035153\)

                \(x=\left(-2035153\right)\div2017\)

                \(x=-1009\)

Vậy x = -1009

Answer 2

x=-1009

Answer 3

giai thích cách làm

Answer 4

\(\left(x+1\right)+\left(x+2\right)+...+\left(x+2017\right)=0\)

\(\Rightarrow2017x+\left(1+2+...+2017\right)=0\)

\(\Rightarrow2017x+2035153=0\)

\(\Rightarrow2017x=0-2035153\)

\(\Rightarrow2017x=-2035153\)

\(\Rightarrow x=-2035153:2017\)

\(\Rightarrow x=-1009\)

Mk ko chắc lắm!Nhưng bn tk mk nha!