\(\frac{x+1}{1974}+\frac{x+2}{1973}+\frac{x+3}{1972}=3\)
x+1/1974+1+x+2/1973+1+x+3/1972=0
x+1+1974/1974+x+2+1973/1973+x+3+1972/1972=0
x+1975/1974+x+1975/1973+x+1975/1972=0
(x+1975)(1/1974+1/1973+1/1972)=0
=>x+1975=0 vì 1/1974+1/1973+1/1972 Khác 0
=>x=-1975