Question

tìm x biết 

\(\frac{\left(x-1\right)^2}{3}=\frac{24}{2}\)

Answer 1

tìm x biết 

=>(x−1)².2 =24.3

[x-1]².2=72

[x-1]²=72:2

[x-1]²=36

[x-1]²=6²

=>x-1=6

x=6+1

x=7

Answer 2

\(\frac{\left(x-1\right)^2}{3}=\frac{24}{2}\)

\(\frac{\left(x-1\right)^2}{3}=12\)

\(\left(x-1\right)^2=12\cdot3\)

\(\left(x-1\right)^2=36\)

\(\Rightarrow\left(x-1\right)^2=+-6^2\)

+) x-1=6

x=7

x-1=-6

x=-6+1

x=-5

Vậy x=7 và x=-5